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5h^2-10h-75=0
a = 5; b = -10; c = -75;
Δ = b2-4ac
Δ = -102-4·5·(-75)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-40}{2*5}=\frac{-30}{10} =-3 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+40}{2*5}=\frac{50}{10} =5 $
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